If it's not what You are looking for type in the equation solver your own equation and let us solve it.
28n^2-180n-112=0
a = 28; b = -180; c = -112;
Δ = b2-4ac
Δ = -1802-4·28·(-112)
Δ = 44944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44944}=212$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-212}{2*28}=\frac{-32}{56} =-4/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+212}{2*28}=\frac{392}{56} =7 $
| 3/4(12x+6)=-45/2 | | 4x^2-6x+15=0 | | -2=-5t | | 1/3(4x-15+5x)=-5+3 | | 17.16=3g+3.63 | | 6t+(3-(-10t)3=15 | | F(-2)=x^2+2x-5 | | 13+2x=x+13 | | 7243x=210355 | | k+9=6(k-11)k=15 | | x–1=-5 | | -x–1=-5 | | (3x)/(5)+(1)/(6)=(x)/(2)-(1)/(3) | | 3x/2+x/4-2x/3=13/2 | | 68=2(x-4)-8(1-5x) | | 2g+18=16-4(g+7) | | 6=m/12-8 | | 16(x+1)=4(4x+9)-2 | | 1/3x+3+x=180 | | 5x+7x-40=60-8x | | 40=60/x | | 10x+20=-130 | | 65-1x=2x-10 | | 112-180n=-28n^2 | | 117=-13k | | 3/4k-9=2 | | -2x+8=11x-8 | | -4m-3=-2m-3 | | (2w+2)w=70 | | 20r^2-17r-10=0 | | 7/5=1/x+3 | | n3=64 |